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-rw-r--r--find_min_area_conver_ones1.c38
-rw-r--r--find_min_area_conver_ones1.py32
2 files changed, 70 insertions, 0 deletions
diff --git a/find_min_area_conver_ones1.c b/find_min_area_conver_ones1.c
new file mode 100644
index 0000000..3dc66be
--- /dev/null
+++ b/find_min_area_conver_ones1.c
@@ -0,0 +1,38 @@
+// 3195. Find the Minimum Area to Cover All Ones I
+#include "leetcode.h"
+
+/*
+ * you are given a 2d binary array 'grid'. find a rectangle with horizontal and
+ * vertical lines with the smallest area, such that all the 1's in 'grid' lie
+ * inside this rectangle. return the minimum possible area of the rectangle.
+ */
+
+int minimumArea(int **grid, int gridSize, int *gridColSize) {
+ int m = gridSize, n = gridColSize[0];
+ int min_row = m, max_row = -1;
+ int min_col = n, max_col = -1;
+ for (int i = 0; i < m; i++)
+ for (int j = 0; j < n; j++)
+ if (grid[i][j]) {
+ if (i < min_row)
+ min_row = i;
+ if (i > max_row)
+ max_row = i;
+ if (j < min_col)
+ min_col = j;
+ if (j > max_col)
+ max_col = j;
+ }
+ return (max_row - min_row + 1) * (max_col - min_col + 1);
+}
+
+int main() {
+ int g1i[2][3] = {{0, 1, 0}, {1, 0, 1}}, g2i[2][2] = {{1, 0}, {0, 0}};
+ struct two_d_arr g1, g2;
+ two_d_arr_init(&g1, ARRAY_SIZE(g1i), ARRAY_SIZE(g1i[0]), g1i);
+ two_d_arr_init(&g2, ARRAY_SIZE(g2i), ARRAY_SIZE(g2i[0]), g2i);
+ printf("%d\n", minimumArea(g1.arr, g1.row_size, g1.col_size)); // expect: 6
+ printf("%d\n", minimumArea(g2.arr, g2.row_size, g2.col_size)); // expect: 1
+ two_d_arr_free(&g1);
+ two_d_arr_free(&g2);
+}
diff --git a/find_min_area_conver_ones1.py b/find_min_area_conver_ones1.py
new file mode 100644
index 0000000..9374874
--- /dev/null
+++ b/find_min_area_conver_ones1.py
@@ -0,0 +1,32 @@
+# 3195. Find the Minimum Area to Cover All Ones I
+
+"""
+you are given a 2d binary array 'grid'. find a rectangle with horizontal and
+vertical lines with the smallest area, such that all the 1's in 'grid' lie
+inside this rectangle. return the minimum possible area of the rectangle.
+"""
+
+
+class Solution:
+ def minimumArea(self, grid):
+ """
+ :type grid: List[List[int]]
+ :rtype: int
+ """
+ m, n = len(grid), len(grid[0])
+ min_row, max_row = m, -1
+ min_col, max_col = n, -1
+ for i in range(m):
+ for j in range(n):
+ if grid[i][j] == 1:
+ min_row = min(min_row, i)
+ max_row = max(max_row, i)
+ min_col = min(min_col, j)
+ max_col = max(max_col, j)
+ return (max_row - min_row + 1) * (max_col - min_col + 1)
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.minimumArea(grid=[[0, 1, 0], [1, 0, 1]]))
+ print(obj.minimumArea(grid=[[1, 0], [0, 0]]))