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Diffstat (limited to 'incremental_memory_leak.c')
-rw-r--r-- | incremental_memory_leak.c | 43 |
1 files changed, 43 insertions, 0 deletions
diff --git a/incremental_memory_leak.c b/incremental_memory_leak.c new file mode 100644 index 0000000..15b1286 --- /dev/null +++ b/incremental_memory_leak.c @@ -0,0 +1,43 @@ +// 1860. Incremental Memory Leak +#include "leetcode.h" + +/* + * you are given two integer 'memory1' and 'memory2' representing the available + * memory in bits on two memory sticks. there is currently a faulty program + * running that consumes an increasing amount of memory every second. at the + * i'th second (starting from 1), 'i' bits of memory are allocated to the stick + * with more available memory (or from the first memory stick if both have the + * same available memory). if neither stick has at least 'i' bits of available + * memory, the program crashes. return an array containing '[crash_time, + * memory1_crash, memory2_crash]', where 'crash_time' is the time when the + * program crashed and 'memory1_crash' and 'memory2_crash' are the available + * bits of memory in the first and second sticks respectively + */ + +int *memLeak(int memory1, int memory2, int *returnSize) { + *returnSize = 3; + int i = 1, *ans = (int *)malloc((*returnSize) * sizeof(int)); + while (memory1 >= i || memory2 >= i) { + if (memory2 > memory1) + memory2 -= i; + else + memory1 -= i; + i++; + } + ans[0] = i; + ans[1] = memory1; + ans[2] = memory2; + return ans; +} + +int main() { + int rs1, rs2, *ml1 = memLeak(2, 2, &rs1), *ml2 = memLeak(8, 11, &rs2); + for (int i = 0; i < rs1; i++) + printf("%d ", ml1[i]); // expect: 3 1 0 + printf("\n"); + free(ml1); + for (int i = 0; i < rs2; i++) + printf("%d ", ml2[i]); // expect: 6 0 4 + printf("\n"); + free(ml2); +} |