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+# 2873. Maximum Value of an Ordered Triplet I
+
+"""
+you are given a 0-indexed integer array 'nums'. return the maximum value over
+all triplets of indices '(i, j, k)' such that 'i < j < k'. if all such
+triplets have a negative value, return 0. the value of a triplet of indices
+'(i, j, k)' is equal to '(nums[i] - nums[j]) nums[k]'
+"""
+
+
+class Solution(object):
+ def maximumTripletValue(self, nums):
+ """
+ :type nums: List[int]
+ :rtype: int
+ """
+ n = len(nums)
+ if n < 3:
+ return 0
+ ans, curr, diff = 0, nums[0], 0
+ for i in range(1, n):
+ ans = max(ans, diff * nums[i])
+ diff = max(diff, curr - nums[i])
+ curr = max(curr, nums[i])
+ return ans
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.maximumTripletValue(nums=[12, 6, 1, 2, 7]))
+ print(obj.maximumTripletValue(nums=[1, 10, 3, 4, 19]))
+ print(obj.maximumTripletValue(nums=[1, 2, 3]))