angle_between_clock_hands.py (591B)
| # 1344. Angle Between Hands of a Clock
"""
given two numbers, 'hour' and 'minutes', return the smaller angle (in
degrees) formed between the 'hour' and the 'minute' hand. answers within
10^-5 of the actual value will be accepted.
"""
class Solution:
def angleClock(self, hour: int, minutes: int) -> float:
return min(abs(30 * hour - 5.5 * minutes), 360 - abs(30 * hour - 5.5 * minutes))
if __name__ == "__main__":
obj = Solution()
print(obj.angleClock(hour=12, minutes=30))
print(obj.angleClock(hour=3, minutes=30))
print(obj.angleClock(hour=3, minutes=15))
|
