check_parentheses_valid.py (1578B)
| # 2116. Check if a Parentheses String Can Be Valid
"""
a parentheses string is a non-empty string consisting only of '(' and ')'. it
is valid if any of the following conditions is true: it is '()', it can be
written as 'AB' where 'A' and 'B' are valid parentheses, it can be written as
'(A)' where 'A' is a valid parentheses string. you are given a parentheses
string 's' and a string 'locked', both of length 'n'. 'locked' is a binary
string consistion only of '0's and '1's. for each indiex 'i' of 'locked'.
"""
class Solution(object):
def canBeValid(self, s, locked):
"""
:type s: str
:type locked: str
:rtype: bool
"""
if len(s) % 2 == 1:
return False
total = open = closed = 0
for i in range(len(s) - 1, -1, -1):
if locked[i] == "0":
total += 1
elif s[i] == "(":
open += 1
elif s[i] == ")":
closed += 1
if total - open + closed < 0:
return False
total = open = closed = 0
for i in range(len(s)):
if locked[i] == "0":
total += 1
elif s[i] == "(":
open += 1
elif s[i] == ")":
closed += 1
if total + open - closed < 0:
return False
return True
if __name__ == "__main__":
obj = Solution()
print(obj.canBeValid(s="))()))", locked="010100"))
print(obj.canBeValid(s="()()", locked="0000"))
print(obj.canBeValid(s=")", locked="0"))
|
