max_area_longest_diag_rect.py (951B)
| # 3000. Maximum Area of Longest Diagonal Rectangle
"""
you are given a 2d 0-indexed integer array 'dimensions'. for all indices 'i',
'0 <= i < dimensions.size', 'dimensions[i][0]' represents the length and
'dimensions[i][1]' represents the width of the rectangle 'i'. return the area
of the rectangle having the longest diagonal, return the area of the
rectangle having the maximum area.
"""
class Solution(object):
def areaOfMaxDiagonal(self, dimensions):
"""
:type dimensions: List[List[int]]
:rtype: int
"""
ans, area = 0, 0
for l, w in dimensions:
curr = l * l + w * w
if curr > area or (curr == area and l * w > ans):
area = curr
ans = l * w
return ans
if __name__ == "__main__":
obj = Solution()
print(obj.areaOfMaxDiagonal(dimensions=[[9, 3], [8, 6]]))
print(obj.areaOfMaxDiagonal(dimensions=[[3, 4], [4, 3]]))
|
