minimum_array_end.py (780B)
| # 3133. Minimum Array End
"""
you are given two integers 'n' and 'x'. you have to construct an array of
positive integers 'nums'. of size 'n' where for every '0 <= i < n - 1',
'nums[i + 1]' is greater than 'nums[i]', and the result of the bitwise and
operation between all elements of 'nums' is 'x'. return the minimum possible
value of 'nums[n - 1]'
"""
class Solution(object):
def minEnd(self, n, x):
"""
:type n: int
:type x: int
:rtype: int
"""
n -= 1
b = 1
for i in range(64):
if b & x == 0:
x |= (n & 1) * b
n >>= 1
b <<= 1
return x
if __name__ == "__main__":
obj = Solution()
print(obj.minEnd(3, 4))
print(obj.minEnd(2, 7))
|
