reverse_linked_list.py (757B)
| # 206. Reverse Linked List
"""
given the 'head' of a singly linked list, reverse the list, and return the
reversed list.
"""
# Definition for singly-linked list.
class ListNode(object):
def __init__(self, val=0, next=None):
self.val = val
self.next = next
class Solution(object):
def reverseList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
prev = None
while head:
curr = head
head = head.next
curr.next = prev
prev = curr
return prev
if __name__ == "__main__":
obj = Solution()
print(obj.reverseList(head=[1, 2, 3, 4, 5]))
print(obj.reverseList(head=[1, 2]))
print(obj.reverseList(head=[]))
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