From 32b3c8cc7a72294298aabcedc2033b06f2a7ca5e Mon Sep 17 00:00:00 2001 From: Jack Sangdahl Date: Sat, 11 Jan 2025 12:58:39 -0700 Subject: 2116. check if a parentheses string can be valid --- check_parentheses_valid.py | 49 ++++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 49 insertions(+) create mode 100644 check_parentheses_valid.py (limited to 'check_parentheses_valid.py') diff --git a/check_parentheses_valid.py b/check_parentheses_valid.py new file mode 100644 index 0000000..a6f5c28 --- /dev/null +++ b/check_parentheses_valid.py @@ -0,0 +1,49 @@ +# 2116. Check if a Parentheses String Can Be Valid + +""" +a parentheses string is a non-empty string consisting only of '(' and ')'. it +is valid if any of the following conditions is true: it is '()', it can be +written as 'AB' where 'A' and 'B' are valid parentheses, it can be written as +'(A)' where 'A' is a valid parentheses string. you are given a parentheses +string 's' and a string 'locked', both of length 'n'. 'locked' is a binary +string consistion only of '0's and '1's. for each indiex 'i' of 'locked'. +""" + + +class Solution(object): + def canBeValid(self, s, locked): + """ + :type s: str + :type locked: str + :rtype: bool + """ + if len(s) % 2 == 1: + return False + total = open = closed = 0 + for i in range(len(s) - 1, -1, -1): + if locked[i] == "0": + total += 1 + elif s[i] == "(": + open += 1 + elif s[i] == ")": + closed += 1 + if total - open + closed < 0: + return False + total = open = closed = 0 + for i in range(len(s)): + if locked[i] == "0": + total += 1 + elif s[i] == "(": + open += 1 + elif s[i] == ")": + closed += 1 + if total + open - closed < 0: + return False + return True + + +if __name__ == "__main__": + obj = Solution() + print(obj.canBeValid(s="))()))", locked="010100")) + print(obj.canBeValid(s="()()", locked="0000")) + print(obj.canBeValid(s=")", locked="0")) -- cgit v1.2.3