From 8f773da1404a7c3f1e4a9ccde3d7b33c27d8c3be Mon Sep 17 00:00:00 2001 From: Jack Sangdahl Date: Wed, 30 Apr 2025 11:57:26 -0600 Subject: 2749. minimum operations to make the integer zero --- min_ops_make_int_zero.c | 36 ++++++++++++++++++++++++++++++++++++ 1 file changed, 36 insertions(+) create mode 100644 min_ops_make_int_zero.c (limited to 'min_ops_make_int_zero.c') diff --git a/min_ops_make_int_zero.c b/min_ops_make_int_zero.c new file mode 100644 index 0000000..95d7255 --- /dev/null +++ b/min_ops_make_int_zero.c @@ -0,0 +1,36 @@ +// 2749. Minimum Operations to Make the Integer Zero +#include "leetcode.h" + +/* + * you are given two integers 'nums1' and 'nums2'. in one operation you can + * choose integer 'i' in the range '[0, 60]' and subtract '2^i + num2' from + * 'num1'. return the integer denoting the minimum number of operations needed + * to make 'nums1' equal to 0. if it is impossible to make 'nums1' equal to 0, + * return -1. + */ + +int bit_cnt(long long num) { + int cnt = 0; + while (num > 0) { + cnt += num & 1; + num >>= 1; + } + return cnt; +} + +int makeTheIntegerZero(int num1, int num2) { + if (num1 < num2) + return -1; + for (int i = 0; i <= 100; i++) { + long long diff = num1 - 1LL * num2 * i; + int bits = bit_cnt(diff); + if (bits <= i && i <= diff) + return i; + } + return -1; +} + +int main() { + printf("%d\n", makeTheIntegerZero(3, -2)); // expect: 3 + printf("%d\n", makeTheIntegerZero(5, 7)); // expect: -1 +} -- cgit v1.2.3