# 2487. Remove Nodes From Linked List """ given the 'head' of a linked list, remove evey node which has a node with a greater value anywhere to the right side of it. return the 'head' of the modified linked list. """ # Definition for singly-linked list. class ListNode(object): def __init__(self, val=0, next=None): self.val = val self.next = next class Solution(object): def removeNodes(self, head): """ :type head: Optional[ListNode] :rtype: Optional[ListNode] """ if not head: return None head.next = self.removeNodes(head.next) if head.next and head.val < head.next.val: return head.next return head