# 1310. XOR Queries of a Subarray """ you are given an array 'arr' of positive integers. you are also given the array 'queries' where 'queries[i] = [left_i, right_i]'. for each query 'i' compute the xor of elements from 'left_i' to 'right_i'. return an array 'answer' where 'answer[i]' is the answer to the i'th query """ class Solution(object): def xorQueries(self, arr, queries): """ :type arr: List[int] :type queries: List[List[int]] :rtype: List[int] """ for i in range(len(arr) - 1): arr[i + 1] ^= arr[i] return [arr[j] ^ arr[i - 1] if i else arr[j] for i, j in queries] if __name__ == "__main__": obj = Solution() print(obj.xorQueries(arr=[1, 3, 4, 8], queries=[[0, 1], [1, 2], [0, 3], [3, 3]])) print(obj.xorQueries(arr=[4, 8, 2, 10], queries=[[2, 3], [1, 3], [0, 0], [0, 3]]))