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authorJack Sangdahl <[email protected]>2024-10-25 13:27:03 -0600
committerJack Sangdahl <[email protected]>2024-10-26 00:38:09 -0600
commit5ea66938849e5a07d6d7c9d20256421d43680457 (patch)
tree7789796c13919d273eae7d390fd7b90939e03cda
parenta43f21d0aff66470e17b47febcd01e67bbdce5f6 (diff)
downloadleetcode-5ea66938849e5a07d6d7c9d20256421d43680457.tar.gz
leetcode-5ea66938849e5a07d6d7c9d20256421d43680457.zip
2967. minimum cost to make array equalidromic
-rw-r--r--min_cost_arr_equalindromic.c64
-rw-r--r--min_cost_arr_equalindromic.py40
2 files changed, 104 insertions, 0 deletions
diff --git a/min_cost_arr_equalindromic.c b/min_cost_arr_equalindromic.c
new file mode 100644
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--- /dev/null
+++ b/min_cost_arr_equalindromic.c
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+// 2967. Minimum Cost to Make Array Equalindromic
+#include "leetcode.h"
+
+/*
+ * you are given a 0-indexed integer array 'nums' having length 'n'. you are
+ * allowed to perform a special move any number of times on 'nums'. in one
+ * special move, you perform the following steps in order: choose an index 'i'
+ * in the range '[0, n - 1]' and a positive integer 'x', add '|nums[i] - x|' to
+ * the total cost, and change the value of 'nums[i]' to 'x'. a palindromic
+ * number is a positive integer that remains the same when its digits are
+ * reversed. an array is considered equalindromic if all the elements in the
+ * array are equal to an integer 'y', where 'y' is a palindromic number less
+ * than 10^9. return an integer denoting the minimum possible total cost to make
+ * 'nums' equalindromic by performing any number of special moves
+ */
+
+bool is_palindrome(int num) {
+ if (num < 0)
+ return false;
+ int reverse = 0, original = num;
+ while (num) {
+ int digit = num % 10;
+ if (reverse > (INT_MAX - digit) / 10)
+ return false;
+ reverse = reverse * 10 + digit;
+ num /= 10;
+ }
+ return reverse == original;
+}
+
+long long calculate_cost(int *nums, int numsSize, int target) {
+ long long cost = 0;
+ for (int i = 0; i < numsSize; i++)
+ cost += abs(nums[i] - target);
+ return cost;
+}
+
+int cmp(const void *a, const void *b) { return (*(int *)a - *(int *)b); }
+
+long long minimumCost(int *nums, int numsSize) {
+ qsort(nums, numsSize, sizeof(int), cmp);
+ int median = nums[numsSize / 2];
+ int lower = median - 100000, upper = median + 100000;
+ if (lower < 1)
+ lower = 1;
+ if (upper > 1000000000)
+ upper = 1000000000;
+ long long min_cost = LLONG_MAX;
+ for (int i = 0; i <= upper; i++)
+ if (is_palindrome(i)) {
+ long long curr_cost = calculate_cost(nums, numsSize, i);
+ if (curr_cost < min_cost)
+ min_cost = curr_cost;
+ }
+ return min_cost;
+}
+
+int main() {
+ int n1[] = {1, 2, 3, 4, 5}, n2[] = {10, 12, 13, 14, 15},
+ n3[] = {22, 33, 22, 33, 22};
+ printf("%lld\n", minimumCost(n1, ARRAY_SIZE(n1))); // expect: 6
+ printf("%lld\n", minimumCost(n2, ARRAY_SIZE(n2))); // expect: 11
+ printf("%lld\n", minimumCost(n3, ARRAY_SIZE(n3))); // expect: 22
+}
diff --git a/min_cost_arr_equalindromic.py b/min_cost_arr_equalindromic.py
new file mode 100644
index 0000000..2594149
--- /dev/null
+++ b/min_cost_arr_equalindromic.py
@@ -0,0 +1,40 @@
+# 2967. Minimum Cost to Make Array Equalindromic
+
+"""
+you are given a 0-indexed integer array 'nums' having length 'n'. you are
+allowed to perform a special move any number of times on 'nums'. in one
+special move, you perform the following steps in order: choose an index 'i'
+in the range '[0, n - 1]' and a positive integer 'x', add '|nums[i] - x|' to
+the total cost, and change the value of 'nums[i]' to 'x'. a palindromic
+number is a positive integer that remains the same when its digits are
+reversed. an array is considered equalindromic if all the elements in the
+array are equal to an integer 'y', where 'y' is a palindromic number less
+than 10^9. return an integer denoting the minimum possible total cost to make
+'nums' equalindromic by performing any number of special moves
+"""
+
+
+class Solution(object):
+ def minimumCost(self, nums):
+ """
+ :type nums: List[int]
+ :rtype: int
+ """
+ nums.sort()
+ palindrome = lambda x: str(x) == str(x)[::-1]
+ left = right = nums[len(nums) // 2]
+ while not palindrome(left):
+ left -= 1
+ while not palindrome(right):
+ right += 1
+ return min(
+ sum(map(lambda x: abs(x - left), nums)),
+ sum(map(lambda x: abs(x - right), nums)),
+ )
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.minimumCost(nums=[1, 2, 3, 4, 5]))
+ print(obj.minimumCost(nums=[10, 12, 13, 14, 15]))
+ print(obj.minimumCost(nums=[22, 33, 22, 33, 22]))