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authorJack Sangdahl <[email protected]>2025-05-19 23:02:14 -0600
committerJack Sangdahl <[email protected]>2025-05-19 23:02:14 -0600
commitefde03c42facb93ae6dcefb0ba795463fed77f72 (patch)
tree8eeb2f0db0bc406fe38b64ac77d9caef8404f58f
parentc585422d643252924194811d6204f773a35ca5e0 (diff)
downloadleetcode-efde03c42facb93ae6dcefb0ba795463fed77f72.tar.gz
leetcode-efde03c42facb93ae6dcefb0ba795463fed77f72.zip
3355. zero array transform 1
-rw-r--r--zero_array_transformation1.c45
-rw-r--r--zero_array_transformation1.py36
2 files changed, 81 insertions, 0 deletions
diff --git a/zero_array_transformation1.c b/zero_array_transformation1.c
new file mode 100644
index 0000000..45f388c
--- /dev/null
+++ b/zero_array_transformation1.c
@@ -0,0 +1,45 @@
+// 3355. Zero Array Transformation I
+#include "leetcode.h"
+
+/*
+ * you are given an integer array 'nums' of length 'n' and a 2d array 'queries'
+ * where 'queries[i] = [li, ri]'. for each 'queries[i]' select a subset of
+ * indices within the range '[li, ri]' in 'nums' and decrement the values at the
+ * selected indices by 1. a zero array is an array where all elements are equal
+ * to 0. return true if it is possible to transform 'nums' into a zero array
+ * after processing all the queries sequentially, otherwise return false.
+ */
+
+bool isZeroArray(int *nums, int numsSize, int **queries, int queriesSize,
+ int *queriesColSize) {
+ int *freq = (int *)calloc(numsSize + 1, sizeof(int));
+ for (int i = 0; i < queriesSize; i++) {
+ int l = queries[i][0], r = queries[i][1];
+ freq[l]++;
+ freq[r + 1]--;
+ }
+ int cnt = 0;
+ for (int i = 0; i < numsSize; i++) {
+ cnt += freq[i];
+ if (nums[i] > cnt) {
+ free(freq);
+ return false;
+ }
+ }
+ free(freq);
+ return true;
+}
+
+int main() {
+ int n1[] = {1, 0, 1}, q1i[1][2] = {{0, 2}};
+ int n2[] = {4, 3, 2, 1}, q2i[2][2] = {{1, 3}, {0, 2}};
+ struct two_d_arr q1, q2;
+ two_d_arr_init(&q1, ARRAY_SIZE(q1i), ARRAY_SIZE(q1i[0]), q1i);
+ two_d_arr_init(&q2, ARRAY_SIZE(q2i), ARRAY_SIZE(q2i[0]), q2i);
+ printf("%d\n", isZeroArray(n1, ARRAY_SIZE(n1), q1.arr, q1.row_size,
+ q1.col_size)); // expect: 1
+ printf("%d\n", isZeroArray(n2, ARRAY_SIZE(n2), q2.arr, q2.row_size,
+ q2.col_size)); // expect: 0
+ two_d_arr_free(&q1);
+ two_d_arr_free(&q2);
+}
diff --git a/zero_array_transformation1.py b/zero_array_transformation1.py
new file mode 100644
index 0000000..e4cc270
--- /dev/null
+++ b/zero_array_transformation1.py
@@ -0,0 +1,36 @@
+# 3355. Zero Array Transformation I
+
+"""
+you are given an integer array 'nums' of length 'n' and a 2d array 'queries'
+where 'queries[i] = [li, ri]'. for each 'queries[i]' select a subset of
+indices within the range '[li, ri]' in 'nums' and decrement the values at the
+selected indices by 1. a zero array is an array where all elements are equal
+to 0. return true if it is possible to transform 'nums' into a zero array
+after processing all the queries sequentially, otherwise return false.
+"""
+
+
+class Solution(object):
+ def isZeroArray(self, nums, queries):
+ """
+ :type nums: List[int]
+ :type queries: List[List[int]]
+ :rtype: bool
+ """
+ n = len(nums)
+ freq = [0] * (n + 1)
+ for l, r in queries:
+ freq[l] += 1
+ freq[r + 1] -= 1
+ cnt = 0
+ for i, j in enumerate(nums):
+ cnt += freq[i]
+ if j > cnt:
+ return False
+ return True
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.isZeroArray(nums=[1, 0, 1], queries=[[0, 2]]))
+ print(obj.isZeroArray(nums=[4, 3, 2, 1], queries=[[1, 3], [0, 2]]))