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authorJack Sangdahl <[email protected]>2025-01-09 09:37:42 +0100
committerJack Sangdahl <[email protected]>2025-01-09 09:37:42 +0100
commit2d159f42638f87dfca97a0ab50099b0eef651e5e (patch)
treeb0358fe5417b2fac0b498e4894d48186c812f010 /counting_words_given_prefix.py
parent04d1609e0d5f554d23c19bc0629d0c3d697a87a1 (diff)
downloadleetcode-2d159f42638f87dfca97a0ab50099b0eef651e5e.tar.gz
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2185. counting words with a given prefix
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+# 2185. Counting Words With a Given Prefix
+
+"""
+you are given an array of strings 'words' and a string 'pref'. return the
+number of strings in 'words' that contain 'pref' as a prefix. a prefix of a
+string 's' is any leading contiguous substring of 's'.
+"""
+
+
+class Solution(object):
+ def prefixCount(self, words, pref):
+ """
+ :type words: List[str]
+ :type pref: str
+ :rtype: int
+ """
+ cnt = 0
+ for i in words:
+ if i.startswith(pref):
+ cnt += 1
+ return cnt
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.prefixCount(words=["pay", "attention", "practice", "attend"], pref="at"))
+ print(obj.prefixCount(words=["leetcode", "win", "loops", "success"], pref="code"))