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author | Jack Sangdahl <[email protected]> | 2024-09-10 18:16:11 -0600 |
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committer | Jack Sangdahl <[email protected]> | 2024-09-10 18:16:11 -0600 |
commit | 04058b633ddcf3858445bada106bbbc030cc6aac (patch) | |
tree | a2e033ec217a49ff5ac48e5e0105630ea7e54159 /freedom_trail.c | |
parent | 309241c48abc953042965d0735e17f098c426105 (diff) | |
download | leetcode-04058b633ddcf3858445bada106bbbc030cc6aac.tar.gz leetcode-04058b633ddcf3858445bada106bbbc030cc6aac.zip |
514. freedom trail
Diffstat (limited to 'freedom_trail.c')
-rw-r--r-- | freedom_trail.c | 53 |
1 files changed, 53 insertions, 0 deletions
diff --git a/freedom_trail.c b/freedom_trail.c new file mode 100644 index 0000000..b9f1eb7 --- /dev/null +++ b/freedom_trail.c @@ -0,0 +1,53 @@ +// 514. Freedom Trail +#include "leetcode.h" + +/* + * in the video game fallout 4, the quest "road to freeom" requires players to + * reach a metal dial call the "freedom trail ring" and use the dial to spell a + * specific keyword to open the door. given a string 'rint' that represents the + * code engraved on the outer ring and another string 'key' that represents the + * keyword that needs to be spelled, return the minimum number of steps to spell + * all of the characters in the keyword. initially, the first character of the + * ring is aligned at "12:00" diretion. you should spell all the characters in + * 'key' one by rotating 'ring' clockwise or anticlockwise to make each + * character of the string aligned at the "12:00" direction and then by pressing + * the center button. at the stage of rotating the ring to spell the key + * character 'key[i]' you can rotate the ring clockwise or anticlockwise by one + * place, which counts as one step. the final purpose of the rotation is to + * align one of 'ring's characters at "12:00" direction, where this character + * must equal 'key[i]' + */ + +int dp[101][101]; + +int dfs(char *ring, char *key, int ring_size, int key_size, int ring_idx, + int key_idx) { + if (key_idx == key_size) + return 0; + if (dp[key_idx][ring_idx] != -1) + return dp[key_idx][ring_idx]; + int min_step = 1e9; + for (int i = 0; i < ring_size; i++) + if (ring[i] == key[key_idx]) { + int cw = (ring_idx + ring_size - i) % ring_size; + int ccw = (i + ring_size - ring_idx) % ring_size; + int step = fmin(cw, ccw) + 1 + + dfs(ring, key, ring_size, key_size, i, key_idx + 1); + min_step = fmin(min_step, step); + } + dp[key_idx][ring_idx] = min_step; + return min_step; +} + +int findRotateSteps(char *ring, char *key) { + int ring_size = strlen(ring); + int key_size = strlen(key); + memset(dp, -1, sizeof(dp)); + return dfs(ring, key, ring_size, key_size, 0, 0); +} + +int main() { + char *r1 = "godding", *k1 = "gd", *r2 = "godding", *k2 = "godding"; + printf("%d\n", findRotateSteps(r1, k1)); // expect: 4 + printf("%d\n", findRotateSteps(r2, k2)); // expect: 13 +} |