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authorjack <[email protected]>2024-06-14 13:13:15 -0600
committerjack <[email protected]>2024-06-14 13:13:15 -0600
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tree96df922dae2a5073d9a50ea70c7aae6aa37e3ebe /max_repeat_substr.py
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+# 1668. Maximum Repeating Substring
+
+"""
+for a string 'sequence', a string 'word' is 'k'-repeating if 'word'
+concatenated 'k' times is a substring of 'sequence'. the 'word's maximum
+'k'-repeating value is the highest value 'k' where 'word' is 'k'-repeating in
+'sequence'. if 'word' is not a substring of 'sequence', 'word's maximum
+'k'-repeating value is 0. given strings 'sequence' and 'word', return the
+maximum 'k'-repeating value of 'word' in 'sequence'.
+"""
+
+
+class Solution(object):
+ def maxRepeating(self, sequence, word):
+ """
+ :type sequence: str
+ :type word: str
+ :rtype: int
+ """
+ n, m = len(sequence), len(word)
+ max_repeat = n
+ failure = [0] * (m * max_repeat + 1)
+ repeat_words = word * max_repeat + "$"
+ ans, j = 0, 0
+ for i in range(1, len(repeat_words)):
+ while j > 0 and repeat_words[j] != repeat_words[i]:
+ j = failure[j - 1]
+ j += repeat_words[j] == repeat_words[i]
+ failure[i] = j
+ j = 0
+ for i, c in enumerate(sequence):
+ while j > 0 and repeat_words[j] != c:
+ j = failure[j - 1]
+ j += repeat_words[j] == c
+ ans = max(ans, j // m)
+ return ans
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.maxRepeating("ababc", "ab")) # expect: 2
+ print(obj.maxRepeating("ababc", "ba")) # expect: 1
+ print(obj.maxRepeating("ababc", "ac")) # expect: 0