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authorjack <[email protected]>2024-06-14 13:13:15 -0600
committerjack <[email protected]>2024-06-14 13:13:15 -0600
commitd343a3b18dbaca9297d4f7b2280c4a16f0a5c8aa (patch)
tree96df922dae2a5073d9a50ea70c7aae6aa37e3ebe /max_subseq_score.cpp
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+// 2542. Maximum Subsequence Score
+#include "leetcode.h"
+
+/*
+ * given two 0-indexed integer arrays 'num1' and 'nums2' of equal length 'n' and
+ * a positive integer 'k'. you must choose a subsequence of indices from 'nums1'
+ * of length 'k'. for chosen indices 'i0, i1, ..., ik-1', your score is defined
+ * as
+ * - the sum of the selected elements from 'nums1' multiplied with the minimum
+ * of the selected elements from 'nums2'
+ * - it can defined simply as '(num1[i0] + nums1[i1] + ... + nums1[ik - 1]) *
+ * min(nums2[i0], nums2[i1], ..., nums2[ik - 1])' return the maximum possible
+ * score. a subseqnce of indices of an array is a set that can be derived from
+ * the set '{0, 1, ..., n - 1}' by deleting no elements
+ */
+
+class Solution {
+public:
+ long long maxScore(vector<int> &nums1, vector<int> &nums2, int k) {
+ int n = nums1.size();
+ vector<pair<int, int>> ess(n);
+ for (int i = 0; i < n; ++i)
+ ess[i] = {nums2[i], nums1[i]};
+ sort(rbegin(ess), rend(ess));
+ long long sum_s = 0, ans = 0;
+ priority_queue<int, vector<int>, greater<int>> pq;
+ for (auto &[e, s] : ess) {
+ pq.emplace(s);
+ sum_s += s;
+ if (pq.size() > k) {
+ sum_s -= pq.top();
+ pq.pop();
+ }
+ if (pq.size() == k)
+ ans = max(ans, sum_s * e);
+ }
+ return ans;
+ }
+};
+
+int main() {
+ Solution obj;
+ vector<int> n11 = {1, 3, 3, 2}, n21 = {2, 1, 3, 4};
+ vector<int> n12 = {4, 2, 3, 1, 1}, n22 = {7, 5, 10, 9, 6};
+ printf("%lld\n", obj.maxScore(n11, n21, 3)); // expect: 12
+ printf("%lld\n", obj.maxScore(n12, n22, 1)); // expect: 30
+}