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authorJack Sangdahl <[email protected]>2024-07-24 20:11:38 -0600
committerJack Sangdahl <[email protected]>2024-07-24 20:11:38 -0600
commit232da4e463a0e5394576a286cf73ec2f313a50a8 (patch)
treeb3bc3939f4099d838ae9cfeee615deabf674523a /reorder_data_log_files.py
parent5b5421ccc8448611e95631299a5b5ab2b030a24e (diff)
downloadleetcode-232da4e463a0e5394576a286cf73ec2f313a50a8.tar.gz
leetcode-232da4e463a0e5394576a286cf73ec2f313a50a8.zip
937. reorder data in log files
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+# 937. Reorder Data in Log Files
+
+"""
+given an array of 'logs'. each log is a space delimited sting of words where
+the first word is the identifier. there are two types of logs. letter logs
+where all words consist of lowercase english letters, and digit logs where
+all words consist of digits. reorder thesse logs so that the letter logs come
+before the digit logs, the letter logs are sorted lexicographically by their
+contents. if their contents are the same, then sort them lexicographically by
+their identifiers, the digit logs maintain their relative order. return the
+final order of the logs.
+"""
+
+
+class Solution(object):
+ def reorderLogFiles(self, logs):
+ """
+ :type logs: List[str]
+ :rtype: List[str]
+ """
+ digits, letters = [], []
+ for l in logs:
+ if l.split()[1].isdigit():
+ digits.append(l)
+ else:
+ letters.append(l)
+ letters.sort(key=lambda x: x.split()[1])
+ letters.sort(key=lambda x: x.split()[1:])
+ ans = letters + digits
+ return ans
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(
+ obj.reorderLogFiles(
+ logs=[
+ "dig1 8 1 5 1",
+ "let1 art can",
+ "dig2 3 6",
+ "let2 own kit dig",
+ "let3 art zero",
+ ]
+ )
+ )
+ print(
+ obj.reorderLogFiles(
+ logs=[
+ "a1 9 2 3 1",
+ "g1 act car",
+ "zo4 4 7",
+ "ab1 off key dog",
+ "a8 act zoo",
+ ]
+ )
+ )