diff options
-rw-r--r-- | stone_game2.c | 10 | ||||
-rw-r--r-- | stone_game2.py | 42 |
2 files changed, 46 insertions, 6 deletions
diff --git a/stone_game2.c b/stone_game2.c index b1b2092..ed142e9 100644 --- a/stone_game2.c +++ b/stone_game2.c @@ -1,7 +1,5 @@ // 1140. Stone Game II -#include <math.h> -#include <stdio.h> -#include <stdlib.h> +#include "leetcode.h" /* * alice and bob continue their games with piles of stones. there are a number @@ -16,10 +14,10 @@ int stoneGameII(int *piles, int piles_size) { int n = piles_size; - int *sum = malloc((n + 1) * sizeof(int)); - int **dp = malloc((n + 1) * sizeof(int *)); + int *sum = (int *)malloc((n + 1) * sizeof(int)); + int **dp = (int **)malloc((n + 1) * sizeof(int *)); for (int i = 0; i <= n; i++) - dp[i] = calloc(n + 1, sizeof(int)); + dp[i] = (int *)calloc(n + 1, sizeof(int)); sum[n] = 0; for (int i = n - 1; i >= 0; i--) sum[i] = sum[i + 1] + piles[i]; diff --git a/stone_game2.py b/stone_game2.py new file mode 100644 index 0000000..46ead18 --- /dev/null +++ b/stone_game2.py @@ -0,0 +1,42 @@ +# 1140. Stone Game II + +""" +alice and bob continue their games with piles of stones. there are a number +of piles arranged in a row, and each pile has a positive integer number of +stones 'piles[i]'. the objective of the game is to end with the most stones. +alice and bob take turns, with alice starting first. initiall, 'M = 1'. on +each player's turn, that player can take all the stones on the 'X' remaining +piles, where '1 <= X <= 2M'. then, we set 'M = max(M, X)'. the game continues +until all the stones have been take. assuming alice and bob play optimally, +return maximum stones alice can get. +""" + + +class Solution(object): + def stoneGameII(self, piles): + """ + :type piles: List[int] + :rtype: int + """ + + def dp(x, y, z): + if y == len(piles): + return 0 + if x == 0: + curr, res = 0, float("-inf") + for i in range(1, min(z * 2, len(piles) - y) + 1): + curr += piles[y + i - 1] + res = max(res, curr + dp(1, y + i, max(i, z))) + else: + res = float("inf") + for i in range(1, min(z * 2, len(piles) - y) + 1): + res = min(res, dp(0, y + i, max(i, z))) + return res + + return dp(0, 0, 1) + + +if __name__ == "__main__": + obj = Solution() + print(obj.stoneGameII(piles=[2, 7, 9, 4, 4])) + print(obj.stoneGameII(piles=[1, 2, 3, 4, 5, 100])) |