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-rw-r--r--len_longest_fib_seq.c56
-rw-r--r--len_longest_fib_seq.py32
2 files changed, 88 insertions, 0 deletions
diff --git a/len_longest_fib_seq.c b/len_longest_fib_seq.c
new file mode 100644
index 0000000..7223f2c
--- /dev/null
+++ b/len_longest_fib_seq.c
@@ -0,0 +1,56 @@
+// 873. Length of Longest Fibonacci Subsequence
+#include "leetcode.h"
+
+/*
+ * a sequence 'x1, x2, ..., xn' is fibonacci like if 'n >= 3' and 'x_i + x_i + 1
+ * == x_i + 2' for all 'i + 2 <= n'. given a strictly increasing 'arr' of
+ * positive integers forming a sequence, return the length of the longest
+ * fibonacci like subsequence of 'arr'. if one does not exist, return 0. a
+ * subsequence is derived from another sequence 'arr' by deleting any number of
+ * elements (including none) from 'arr', without changing the order of the
+ * remaining elements.
+ */
+
+static int a_max;
+
+int helper(int *arr, int *map, int i, int j, int sum) {
+ int cnt = 0;
+ while (sum <= a_max) {
+ if (!map[sum])
+ break;
+ cnt++;
+ i = j;
+ j = map[sum] - 1;
+ sum = arr[i] + arr[j];
+ }
+ return cnt;
+}
+
+int lenLongestFibSubseq(int *arr, int arrSize) {
+ a_max = arr[arrSize - 1];
+ int map_size = a_max + 1;
+ int *map = (int *)calloc(map_size, sizeof(int));
+ int cnt = 0, i, j, sum, tmp;
+ for (int i = 0; i < arrSize; i++)
+ map[arr[i]] = i + 1;
+ for (int i = 0; i < arrSize; i++) {
+ for (int j = i + 1; j < arrSize; j++) {
+ sum = arr[i] + arr[j];
+ if (sum > a_max)
+ break;
+ if (!map[sum])
+ continue;
+ tmp = helper(arr, map, i, j, sum);
+ cnt = fmax(cnt, tmp);
+ }
+ }
+ cnt += 2;
+ free(map);
+ return cnt > 2 ? cnt : 0;
+}
+
+int main() {
+ int a1[] = {1, 2, 3, 4, 5, 6, 7, 8}, a2[] = {1, 3, 7, 11, 12, 14, 18};
+ printf("%d\n", lenLongestFibSubseq(a1, ARRAY_SIZE(a1))); // expect: 5
+ printf("%d\n", lenLongestFibSubseq(a2, ARRAY_SIZE(a2))); // expect: 3
+}
diff --git a/len_longest_fib_seq.py b/len_longest_fib_seq.py
new file mode 100644
index 0000000..619a3db
--- /dev/null
+++ b/len_longest_fib_seq.py
@@ -0,0 +1,32 @@
+# 873. Length of Longest Fibonacci Subsequence
+from collections import defaultdict
+
+"""
+a sequence 'x1, x2, ..., xn' is fibonacci like if 'n >= 3' and 'x_i + x_i + 1
+== x_i + 2' for all 'i + 2 <= n'. given a strictly increasing 'arr' of
+positive integers forming a sequence, return the length of the longest
+fibonacci like subsequence of 'arr'. if one does not exist, return 0. a
+subsequence is derived from another sequence 'arr' by deleting any number of
+elements (including none) from 'arr', without changing the order of the
+remaining elements.
+"""
+
+
+class Solution(object):
+ def lenLongestFibSubseq(self, arr):
+ """
+ :type arr: List[int]
+ :rtype: int
+ """
+ dp, s = defaultdict(int), set(arr)
+ for i in range(len(arr)):
+ for j in range(i):
+ if arr[i] - arr[j] < arr[j] and arr[i] - arr[j] in s:
+ dp[arr[j], arr[i]] = dp.get((arr[i] - arr[j], arr[j]), 2) + 1
+ return max(dp.values() or [0])
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.lenLongestFibSubseq(arr=[1, 2, 3, 4, 5, 6, 7, 8]))
+ print(obj.lenLongestFibSubseq(arr=[1, 3, 7, 11, 12, 14, 18]))