diff options
Diffstat (limited to 'apply_operations_array.py')
-rw-r--r-- | apply_operations_array.py | 35 |
1 files changed, 35 insertions, 0 deletions
diff --git a/apply_operations_array.py b/apply_operations_array.py new file mode 100644 index 0000000..3dc8e7c --- /dev/null +++ b/apply_operations_array.py @@ -0,0 +1,35 @@ +# 2460. Apply Operations to an Array + +""" +you are given 0-indexed array 'nums' of size 'n' consisting of non-negative +integers. you need to apply 'n - 1' operations to this array where in the +i'th operation (0-indexed), you will apply the following on the i'th element +of 'nums': if 'nums[i] == nums[i + 1]', then multiply 'nums[i]' by 2 and set +'nums[i + 1]' to operate 0. otherwise, you skip this operation. after +performing all the operations, shift all the 0's to the end of the array. +return the resulting array. note that the operations are applied sequentially +not all at once. +""" + + +class Solution(object): + def applyOperations(self, nums): + """ + :type nums: List[int] + :rtype: List[int] + """ + j = 0 + for i in range(len(nums)): + if i + 1 < len(nums) and nums[i] == nums[i + 1]: + nums[i] *= 2 + nums[i + 1] = 0 + if nums[i]: + nums[j], nums[i] = nums[i], nums[j] + j += 1 + return nums + + +if __name__ == "__main__": + obj = Solution() + print(obj.applyOperations(nums=[1, 2, 2, 1, 1, 0])) + print(obj.applyOperations(nums=[0, 1])) |