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Diffstat (limited to 'defuse_the_bomb.c')
-rw-r--r-- | defuse_the_bomb.c | 59 |
1 files changed, 59 insertions, 0 deletions
diff --git a/defuse_the_bomb.c b/defuse_the_bomb.c new file mode 100644 index 0000000..7948f14 --- /dev/null +++ b/defuse_the_bomb.c @@ -0,0 +1,59 @@ +// 1652. Defuse the Bomb +#include "leetcode.h" + +/* + * you have a bomb to defuse, and your time is running out. your informer will + * provide you with a circular array 'code' of length 'n' and key 'k'. to + * decrypt the code, you must replace every number. all the numbers are replace + * simultaneously. if 'k > 0', replace the i'th number with the sum of the next + * 'k' numbers. if 'k < 0', replace the i'th number with the sum of the previous + * 'k' numbers. if 'k == 0', replace the i'th number with 0. as 'code' is + * circular, the next element of 'code[n - 1]' is 'code[0]' and the previous + * element of 'code[0]' is 'code[n - 1]'. given the circular array 'code' and an + * integer 'k', return the decrypted code to defuse the bomb + */ + +int *decrypt(int *code, int codeSize, int k, int *returnSize) { + int *ans = (int *)malloc(codeSize * sizeof(int)), n, sum; + if (k) + for (int i = 0; i < codeSize; i++) { + for (int j = 1; j <= k; j++) { + n = code[(i + j) % codeSize]; + sum += n; + } + ans[i] = sum; + n = sum = 0; + } + else if (!k) + for (int i = 0; i < codeSize; i++) + ans[i] = 0; + else + for (int i = 0; i < codeSize; i++) { + for (int j = 1; j <= abs(k); j++) { + n = code[(i + codeSize - j) % codeSize]; + sum += n; + } + ans[i] = sum; + n = sum = 0; + } + *returnSize = codeSize; + return ans; +} + +int main() { + int c1[] = {5, 7, 1, 4}, c2[] = {1, 2, 3, 4}, c3[] = {2, 4, 9, 3}; + int rs1, rs2, rs3; + int *d1 = decrypt(c1, ARRAY_SIZE(c1), 3, &rs1); + int *d2 = decrypt(c2, ARRAY_SIZE(c2), 0, &rs2); + int *d3 = decrypt(c3, ARRAY_SIZE(c3), -2, &rs3); + for (int i = 0; i < rs1; i++) + printf("%d ", d1[i]); // expect: 12 10 16 13 + printf("\n"); + for (int i = 0; i < rs2; i++) + printf("%d ", d2[i]); // expect: 0 0 0 0 + printf("\n"); + for (int i = 0; i < rs3; i++) + printf("%d ", d3[i]); // expect: 12 5 6 13 + printf("\n"); + free(d1), free(d2), free(d3); +} |