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+# 3000. Maximum Area of Longest Diagonal Rectangle
+
+"""
+you are given a 2d 0-indexed integer array 'dimensions'. for all indices 'i',
+'0 <= i < dimensions.size', 'dimensions[i][0]' represents the length and
+'dimensions[i][1]' represents the width of the rectangle 'i'. return the area
+of the rectangle having the longest diagonal, return the area of the
+rectangle having the maximum area.
+"""
+
+
+class Solution(object):
+ def areaOfMaxDiagonal(self, dimensions):
+ """
+ :type dimensions: List[List[int]]
+ :rtype: int
+ """
+ ans, area = 0, 0
+ for l, w in dimensions:
+ curr = l * l + w * w
+ if curr > area or (curr == area and l * w > ans):
+ area = curr
+ ans = l * w
+ return ans
+
+
+if __name__ == "__main__":
+ obj = Solution()
+ print(obj.areaOfMaxDiagonal(dimensions=[[9, 3], [8, 6]]))
+ print(obj.areaOfMaxDiagonal(dimensions=[[3, 4], [4, 3]]))