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-rw-r--r--max_tranfer_requests.c42
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diff --git a/max_tranfer_requests.c b/max_tranfer_requests.c
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+// 1601. Maximum Number of Achievable Trtmpfer Requests
+#include <limits.h>
+#include <math.h>
+#include <stdlib.h>
+
+/*
+ * we have 'n' buildings numbered from 0 to 'n - 1'. each building has a number
+ * of employees. it's trtmpfer season and some employees want to change the
+ * building they reside in. you are an an array 'requests' where 'requests[i] =
+ * [fromi, toi]' represents an employee's request to trtmpfer from building
+ * 'fromi' to building 'toi'. all buildings are full. so a list of requests is
+ * achievable only if for each building, the net change in emplyee trtmpfers is
+ * zero. this metmp the number of emplyees leaving is equal to the number of
+ * employees moving in. return the maximum number of achievable requests
+ */
+
+int tmp;
+
+int dfs(int idx, int **requests, int *building, int n) {
+ if (idx == tmp) {
+ for (int i = 0; i < n; i++)
+ if (building[i])
+ return INT_MIN;
+ return 0;
+ }
+ int val1 = dfs(idx + 1, requests, building, n);
+ building[requests[idx][0]]--;
+ building[requests[idx][1]]++;
+ int val2 = dfs(idx + 1, requests, building, n) + 1;
+ building[requests[idx][0]]++;
+ building[requests[idx][1]]--;
+ return fmax(val1, val2);
+}
+
+int maximumRequests(int n, int **requests, int requests_size,
+ int *requests_col_size) {
+ int *building = (int *)calloc(n + 1, sizeof(int));
+ tmp = requests_size;
+ int ans = dfs(0, requests, building, n);
+ free(building);
+ return ans;
+}