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+// 121. Best Time to Buy and Sell Stock
+#include "leetcode.h"
+
+/*
+ * given an array 'prices' where 'prices[i]' is the price of a given stock on
+ * the ith day. maximise profit by choosing a single day to buy one stock and
+ * choosing a diff day in future to sell stock. return maximum profit achievable
+ * from transaction.
+ */
+
+class Solution {
+public:
+ int maxProfit(vector<int> &prices) {
+ int lsf = INT_MAX, op = 0, pist = 0;
+ for (int i = 0; i < prices.size(); i++) {
+ if (prices[i] < lsf)
+ lsf = prices[i];
+ pist = prices[i] - lsf;
+ if (op < pist)
+ op = pist;
+ }
+ return op;
+ }
+};
+
+int main() {
+ Solution obj;
+ vector<int> p1 = {7, 1, 5, 3, 6, 4}, p2 = {7, 6, 4, 3, 1};
+ cout << obj.maxProfit(p1) << endl; // expect: 5
+ cout << obj.maxProfit(p2) << endl; // expect: 0
+}