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+// 2180. Count Integers With Even Digit Sum
+#include "leetcode.h"
+
+/*
+ * given a positive integer 'num', return the number of positive integersless
+ * than or equal to 'num' whose digit sums are event. the digitsum of a positive
+ * integer is the sum of all of its digits.
+ */
+
+class Solution {
+public:
+ int countEven(int num) {
+ int tmp = num, sum = 0;
+ while (num > 0) {
+ sum += num % 10;
+ num /= 10;
+ }
+ return sum % 2 == 0 ? tmp / 2 : (tmp - 1) / 2;
+ }
+};
+
+int main() {
+ Solution obj;
+ printf("%d\n", obj.countEven(4)); // expect: 2
+ printf("%d\n", obj.countEven(30)); // expect: 14
+}