diff options
Diffstat (limited to 'other/num_enclaves.cpp')
-rw-r--r-- | other/num_enclaves.cpp | 45 |
1 files changed, 0 insertions, 45 deletions
diff --git a/other/num_enclaves.cpp b/other/num_enclaves.cpp deleted file mode 100644 index 2629d65..0000000 --- a/other/num_enclaves.cpp +++ /dev/null @@ -1,45 +0,0 @@ -// 1020. Number of Enclaves -#include "leetcode.h" - -/* - * given an 'm * n' binary matrix grid, where 0 represents a sea - * cell and 1 represents a land cell. a move consists of walking - * from one land cell to another adjacent (4-directionally) land - * cell o walking off the boundary of the 'grid'. return number - * of land cells in 'grid' for which we cannot walk off the - * boundary of the grid in any number of moves. - */ - -class Solution { - int dfs(vvd & grid, int i, int j) { - if (i < 0 || j < 0 || i >= grid.size() || j >= grid[0].size() || - grid[i][j] == 0) - return 0; - grid[i][j] = 0; - return 1 + dfs(grid, i - 1, j) + dfs(grid, i + 1, j) + dfs(grid, i, j - 1) + - dfs(grid, i, j + 1); - } - -public: - int numEnclaves(vvd & grid) { - int ones = 0, zeros = 0; - for (int i = 0; i < grid.size(); i++) - for (int j = 0; j < grid[0].size(); j++) - ones += grid[i][j]; - for (int i = 0; i < grid.size(); i++) - for (int j = 0; j < grid[0].size(); j++) - if ((i == 0 || j == 0 || i == grid.size() - 1 || - j == grid[0].size() - 1) && - grid[i][j] == 1) - zeros += dfs(grid, i, j); - return ones - zeros; - } -}; - -int main() { - Solution obj; - vvd g1 = {{0, 0, 0, 0}, {1, 0, 1, 0}, {0, 1, 1, 0}, {0, 0, 0, 0}}; - vvd g2 = {{0, 1, 1, 0}, {0, 0, 1, 0}, {0, 0, 1, 0}, {0, 0, 0, 0}}; - printf("%d\n", obj.numEnclaves(g1)); // expect: 3 - printf("%d\n", obj.numEnclaves(g2)); // expect: 0 -} |