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// 2180. Count Integers With Even Digit Sum
#include <stdio.h>
/*
* given a positive integer 'num', return the number of positive integersless
* than or equal to 'num' whose digit sums are event. the digitsum of a positive
* integer is the sum of all of its digits.
*/
int countEven(int num) {
int ans = 0;
for (int i = 1; i <= num; i++) {
int val = i, d = 0;
while (val) {
d += val % 10;
val /= 10;
}
if (d % 2 == 0)
ans++;
}
return ans;
}
int main() {
printf("%d\n", countEven(4)); // expect: 2
printf("%d\n", countEven(30)); // expect: 14
}
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