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// 1649. Create Sorted Array through Instructions
#include "leetcode.h"
/*
* given an integer array 'instructions', you are asked to create a sorted array
* from the elements in 'instructions'. you start with an empty container
* 'nums'. for each element from left to right in 'instructions', insert it into
* 'nums'. the cost of each insertion is the minimum of the following: the
* number of elements currently in 'nums' that are strictly less than
* 'instructions[i]', the number of elements currently in 'nums' that are
* strictly greater than 'instructions[i]'. return the total cost to insert all
* elements from 'instructions' into 'nums'. since the answer may be large,
* return it modulo 10^9 + 7
*/
static int arr[10001];
void update(int x) {
while (x < 10001) {
arr[x]++;
x += x & -x;
}
}
int get(int x) {
int res = 0;
while (x > 0) {
res += arr[x];
x -= x & -x;
}
return res;
}
int createSortedArray(int *instructions, int instructionsSize) {
memset(arr, 0, sizeof(arr));
int ans = 0, mod = 1e9 + 7;
for (int i = 0; i < instructionsSize; i++) {
ans =
(ans + fmin(get(instructions[i] - 1), i - get(instructions[i]))) % mod;
update(instructions[i]);
}
return ans;
}
int main() {
int i1[] = {1, 5, 6, 2}, i2[] = {1, 2, 3, 6, 5, 4},
i3[] = {1, 2, 3, 3, 2, 4, 2, 1, 2};
printf("%d\n", createSortedArray(i1, ARRAY_SIZE(i1))); // expect: 1
printf("%d\n", createSortedArray(i2, ARRAY_SIZE(i2))); // expect: 3
printf("%d\n", createSortedArray(i3, ARRAY_SIZE(i3))); // expect: 4
}
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