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// 1566. Detect Pattern of Length M Repeated K or More Times
#include "leetcode.h"
/*
* given an array of positive integers 'arr', find a pattern of length 'm' that
* is repeated 'k' or more times. a pattern is a subarray (consecutive
* subsequence) that consists of one or more values repeated multiple times
* consecutively without overlapping. a pattern is defined by its length and the
* number of repetitions. return true if there exists a pattern of length 'm'
* that is repeated 'k' or more times, otherwise return false
*/
static inline int get_fnv(int *arr, int arrSize) {
int FNV_32_INIT = 0xCAFEEE, FNV_32_PRIME = 0x721;
if (!arr)
return 0;
int64_t hash = FNV_32_INIT;
for (int d = 0; d < arrSize; d++) {
hash ^= arr[d];
hash = (hash * FNV_32_PRIME) & 0xFFFFFFFF;
}
return (int)hash;
}
bool containsPattern(int *arr, int arrSize, int m, int k) {
int n[m], prev = 0, hash = 0, cnt = 0, cnt_max = 0;
for (int u = 0; u <= arrSize; u++) {
cnt = 1, prev = 0, hash = 0;
for (int i = u; i <= arrSize - m; i += m)
for (int j = i; j < m + i; j++)
n[j - i] = arr[j];
prev = hash;
hash = get_fnv(n, m);
if (hash == prev)
cnt++;
else
cnt = 1;
if (cnt >= k)
return true;
}
return false;
}
int main() {
int a1[] = {1, 2, 4, 4, 4, 4}, a2[] = {1, 2, 1, 2, 1, 1, 1, 3},
a3[] = {1, 2, 1, 2, 1, 3};
printf("%d\n", containsPattern(a1, ARRAY_SIZE(a1), 1, 3)); // expect: 1
printf("%d\n", containsPattern(a2, ARRAY_SIZE(a2), 2, 2)); // expect: 1
printf("%d\n", containsPattern(a3, ARRAY_SIZE(a3), 2, 3)); // expect: 0
}
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