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# 1493. Longest Subarray of 1's After Deleting One Element
"""
given a binary array 'nums', you should delete one element from it. return
the size of the longest non-empty subarray containing only 1's in the
resulting array. return 0 if there is no such subarray.
"""
class Solution(object):
def longestSubarray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
left, zeros, ans = 0, 0, 0
for right in range(len(nums)):
if nums[right] == 0:
zeros += 1
while zeros > 1:
if nums[left] == 0:
zeros -= 1
left += 1
ans = max(ans, right - left)
return ans
if __name__ == "__main__":
obj = Solution()
print(obj.longestSubarray(nums=[1, 1, 0, 1]))
print(obj.longestSubarray(nums=[0, 1, 1, 1, 0, 1, 1, 0, 1]))
print(obj.longestSubarray(nums=[1, 1, 1]))
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