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// 1964. Find the Longest Valid Obstacle Course at Each Position
#include "leetcode.h"
/*
* you want to build obstacle courses. you are given a 0-indexed integer array
* 'obstacles' of length 'n' where 'obstacles[i]' describes the height of the
* i'th obstacle. for every index 'i' between 0 and 'n - 1' (inclusive), find
* the length of the longest obstacle course in 'obstacles' such that:
* - you choose any number of obstacles between 0 and 'i' inclusive
* - you must include the i'th obstacle in the course
* - you must put the chosen obstacles in the same order as they appear in
* 'obstacles'
* - every obstacle (except the first) is taller than or the same height as the
* obstacle immediately before it return an array 'ans' of length 'n', where
* 'ans[i]' is the length of the longest obstacle course for index 'i' as
* described aboveeeeeeeee
*/
class Solution {
public:
vector<int> longestObstacleCourseAtEachEachPosition(vector<int> &obstacles) {
vector<int> n;
for (int i = 0; i < obstacles.size(); ++i) {
auto it = upper_bound(n.begin(), n.end(), obstacles[i]);
if (it == n.end()) {
n.push_back(obstacles[i]);
it = prev(n.end());
} else {
*it = obstacles[i];
}
obstacles[i] = it - n.begin() + 1;
}
return obstacles;
}
};
int main() {
Solution obj;
vector<int> o1 = {1, 2, 3, 2}, o2 = {2, 2, 1}, o3 = {3, 1, 5, 6, 4, 2};
for (auto i : obj.longestObstacleCourseAtEachEachPosition(o1))
printf("%d ", i); // expect: 1 2 3 3
printf("\n");
for (auto i : obj.longestObstacleCourseAtEachEachPosition(o2))
printf("%d ", i); // expect: 1 2 1
printf("\n");
for (auto i : obj.longestObstacleCourseAtEachEachPosition(o3))
printf("%d ", i); // expect: 1 1 2 3 2 2
printf("\n");
}
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