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// 1639. Number of Ways to Form a Target String Given a Dictionary
#include "leetcode.h"
/*
* you are given a list of strings of the same length 'words' and a string
* 'target'. your task is to form 'target' using the given 'words'. notice that
* you can use multiple characters from the same string in 'words' provided the
* conditions above are met. return the number of ways to from 'target' from
* 'words'. since the answer may be too large, return it modulo 10^9+7
*/
class Solution {
public:
int numWays(vector<string> &words, string target) {
int n = target.length(), mod = 1e9 + 7;
vector<long> ans(n + 1);
ans[0] = 1;
for (int i = 0; i < words[0].length(); ++i) {
vector<int> cnt(26);
for (auto &w : words)
cnt[w[i] - 'a']++;
for (int j = n - 1; j >= 0; --j)
ans[j + 1] += ans[j] * cnt[target[j] - 'a'] % mod;
}
return ans[n] % mod;
}
};
int main() {
Solution obj;
vector<string> s1 = {"acca", "bbbb", "caca"}, s2 = {"abba", "baab"};
string t1 = "aba", t2 = "bab";
printf("%d\n", obj.numWays(s1, t1)); // expect: 6
printf("%d\n", obj.numWays(s2, t2)); // expect: 4
}
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