blob: 20a6b317622f72a4151b1bf590de20f7f7f412c9 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
|
# 2957. Remove Adjacent Almost-Equal Characters
"""
you are given a 0 indexed string 'word'. in one operation you can pick any
index 'i' of 'word' and change 'word[i]' to any lowercase english letter.
return the minimum number of operations needed to remove all adjacent almost
equal characters from 'word'. two characters 'a' and 'b' are almost equal if
'a == b' or 'a' and 'b' are adjacent in the alphabet
"""
class Solution(object):
def removeAlmostEqualCharacters(self, word):
"""
:type word: str
:rtype: int
"""
i, k = 1, 0
while i + k < len(word):
k += abs(ord(word[i + k]) - ord(word[i + k - 1])) < 2
i += 1
return k
if __name__ == "__main__":
obj = Solution()
print(obj.removeAlmostEqualCharacters("aaaaa"))
print(obj.removeAlmostEqualCharacters("abddez"))
print(obj.removeAlmostEqualCharacters("zyxyxyz"))
|