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// 2197. Replace Non-Coprime Numbers in Array
#include "leetcode.h"
/*
* you are given an array of integers 'nums'. perform the following steps: find
* any two adjacent numbers in 'nums' that are non-coprime, if no such numbers
* are found, stop the process. otherwise, delete the two numbers and replace
* them with their lcm. repeat this process as long as you keep finding two
* adjacent non-coprime integers. return the final modified array. it can be
* shown that replacing adjacent non-coprime numbers in any arbitrary order will
* lead to the same result. two values 'x' and '' aree non-coprime if 'gcd(x, y)
* > 1' where 'gcd(x, y)' is the greatest common denomiator
*/
int gcd(int a, int b) {
while (b != 0) {
int tmp = b;
b = a % b;
a = tmp;
}
return a;
}
int *replaceNonCoprimes(int *nums, int numsSize, int *returnSize) {
int *ans = (int *)malloc(numsSize * sizeof(int)), top = 0;
for (int i = 0; i < numsSize; i++) {
int curr = nums[i];
while (top > 0) {
int prev = ans[top - 1];
int g = gcd(prev, curr);
if (g == 1)
break;
top--;
long long merged = (long long)prev / g * curr;
curr = (int)merged;
}
ans[top++] = curr;
}
*returnSize = top;
return ans;
}
int main() {
int n1[] = {6, 4, 3, 2, 7, 6, 2}, rs1;
int n2[] = {2, 2, 1, 1, 3, 3, 3}, rs2;
int *rnc1 = replaceNonCoprimes(n1, ARRAY_SIZE(n1), &rs1);
int *rnc2 = replaceNonCoprimes(n2, ARRAY_SIZE(n2), &rs2);
for (int i = 0; i < rs1; i++)
printf("%d ", rnc1[i]); // expect: 12 7 6
printf("\n");
for (int i = 0; i < rs2; i++)
printf("%d ", rnc2[i]); // expect: 2 1 1 3
printf("\n");
free(rnc1);
free(rnc2);
}
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