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// 1140. Stone Game II
#include "leetcode.h"
/*
* alice and bob continue their games with piles of stones. there are a number
* of piles arranged in a row, and each pile has a positive integer number of
* stones 'piles[i]'. the objective of the game is to end with the most stones.
* alice and bob take turns, with alice starting first. initiall, 'M = 1'. on
* each player's turn, that player can take all the stones on the 'X' remaining
* piles, where '1 <= X <= 2M'. then, we set 'M = max(M, X)'. the game continues
* until all the stones have been take. assuming alice and bob play optimally,
* return maximum stones alice can get.
*/
int stoneGameII(int *piles, int piles_size) {
int n = piles_size;
int *sum = (int *)malloc((n + 1) * sizeof(int));
int **dp = (int **)malloc((n + 1) * sizeof(int *));
for (int i = 0; i <= n; i++)
dp[i] = (int *)calloc(n + 1, sizeof(int));
sum[n] = 0;
for (int i = n - 1; i >= 0; i--)
sum[i] = sum[i + 1] + piles[i];
for (int i = 0; i < n; ++i)
dp[i][n] = sum[i];
for (int i = n - 1; i >= 0; i--)
for (int m = n - 1; m >= 1; m--)
for (int x = 1; x <= 2 * m && i + x <= n; ++x)
dp[i][m] = fmax(dp[i][m], sum[i] - dp[i + x][(int)fmax(m, x)]);
int ans = dp[0][1];
for (int i = 0; i <= n; i++)
free(dp[i]);
free(dp);
free(sum);
return ans;
}
int main() {
int p1[] = {2, 7, 9, 4, 4};
int p2[] = {1, 2, 3, 4, 5, 100};
printf("%d\n", stoneGameII(p1, 5)); // expect: 10
printf("%d\n", stoneGameII(p2, 6)); // expect: 104
}
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