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author | Jack Sangdahl <[email protected]> | 2025-08-25 20:29:36 -0600 |
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committer | Jack Sangdahl <[email protected]> | 2025-08-25 20:29:36 -0600 |
commit | 93bbf9764ee8020da1c2914d16bc6c9698e3c329 (patch) | |
tree | 9dec46a4c310d9c68220ce687412c778473c4a20 | |
parent | 98eef52499de73f369cc7e4a6e11938a1c6d3367 (diff) | |
download | leetcode-93bbf9764ee8020da1c2914d16bc6c9698e3c329.tar.gz leetcode-93bbf9764ee8020da1c2914d16bc6c9698e3c329.zip |
3000. maximum area of longest diagonal rectangle
-rw-r--r-- | max_area_longest_diag_rect.c | 37 | ||||
-rw-r--r-- | max_area_longest_diag_rect.py | 30 |
2 files changed, 67 insertions, 0 deletions
diff --git a/max_area_longest_diag_rect.c b/max_area_longest_diag_rect.c new file mode 100644 index 0000000..3aa7c8e --- /dev/null +++ b/max_area_longest_diag_rect.c @@ -0,0 +1,37 @@ +// 3000. Maximum Area of Longest Diagonal Rectangle +#include "leetcode.h" + +/* + * you are given a 2d 0-indexed integer array 'dimensions'. for all indices 'i', + * '0 <= i < dimensions.size', 'dimensions[i][0]' represents the length and + * 'dimensions[i][1]' represents the width of the rectangle 'i'. return the area + * of the rectangle having the longest diagonal, return the area of the + * rectangle having the maximum area. + */ + +int areaOfMaxDiagonal(int **dimensions, int dimensionsSize, + int *dimensionsColSize) { + int ans = 0, max = 0; + for (int i = 0; i < dimensionsSize; i++) { + int l = dimensions[i][0], w = dimensions[i][1]; + int curr = l * l + w * w; + if (curr > max || (curr == max && l * w > ans)) { + max = curr; + ans = l * w; + } + } + return ans; +} + +int main() { + int d1i[2][2] = {{9, 3}, {8, 6}}, d2i[2][2] = {{3, 4}, {4, 3}}; + struct two_d_arr d1, d2; + two_d_arr_init(&d1, ARRAY_SIZE(d1i), ARRAY_SIZE(d1i[0]), d1i); + two_d_arr_init(&d2, ARRAY_SIZE(d2i), ARRAY_SIZE(d2i[0]), d2i); + printf("%d\n", + areaOfMaxDiagonal(d1.arr, d1.row_size, d1.col_size)); // expect: 48 + printf("%d\n", + areaOfMaxDiagonal(d2.arr, d2.row_size, d2.col_size)); // expect: 12 + two_d_arr_free(&d1); + two_d_arr_free(&d2); +} diff --git a/max_area_longest_diag_rect.py b/max_area_longest_diag_rect.py new file mode 100644 index 0000000..7789f74 --- /dev/null +++ b/max_area_longest_diag_rect.py @@ -0,0 +1,30 @@ +# 3000. Maximum Area of Longest Diagonal Rectangle + +""" +you are given a 2d 0-indexed integer array 'dimensions'. for all indices 'i', +'0 <= i < dimensions.size', 'dimensions[i][0]' represents the length and +'dimensions[i][1]' represents the width of the rectangle 'i'. return the area +of the rectangle having the longest diagonal, return the area of the +rectangle having the maximum area. +""" + + +class Solution(object): + def areaOfMaxDiagonal(self, dimensions): + """ + :type dimensions: List[List[int]] + :rtype: int + """ + ans, area = 0, 0 + for l, w in dimensions: + curr = l * l + w * w + if curr > area or (curr == area and l * w > ans): + area = curr + ans = l * w + return ans + + +if __name__ == "__main__": + obj = Solution() + print(obj.areaOfMaxDiagonal(dimensions=[[9, 3], [8, 6]])) + print(obj.areaOfMaxDiagonal(dimensions=[[3, 4], [4, 3]])) |